Sewerage Flow in Environmental Engineering for JE Exam | Complete Concept + MCQs

 




1. Concept Explanation (Exam-Focused)

Sewerage Flow is the quantity of wastewater flowing in a sewer system per day, originating mainly from water supplied to the population.

In SSC JE / RRB JE, questions are highly numerical and test:

  • Relation between water demand and sewage flow
  • Peak factor application
  • Components like infiltration & inflow

📌 Golden Exam Concept:

Sewerage flow ≈ 70–85% of water demand


Components of Sewerage Flow

  1. Domestic Sewage – From residential water use
  2. Industrial Sewage – Depends on industry type
  3. Infiltration – Groundwater entering sewers
  4. Inflow – Rainwater entering through manholes

Trap: Infiltration ≠ Inflow (frequently asked)


2. Important Formulas (Highly Repeated)

1️ Average Sewage Flow



Where:
= Sewage flow (MLD)
= Water demand (MLD)


2️ Per Capita Sewage Flow



Where:
= Per capita water demand (LPCD)


3️ Maximum Sewage Flow



Where:
Peak factor


4️ Minimum Sewage Flow



🧠 Mnemonic Trick:
“Water × 0.8 → Sewage → × Peak”


3. Short Notes / One-Liners (Last-Day Revision)

Sewage flow is always less than water demand
Design of sewers is based on maximum flow
Infiltration is unavoidable
Inflow can be controlled by proper design
Peak sewage flow occurs morning & evening


4. PYQ Patterns (SSC JE / RRB JE)

🔹 Conversion of LPCD → MLD
🔹 Applying 0.8 factor directly
🔹 MCQs on difference between infiltration & inflow
🔹 Peak factor misuse (2 vs 3)

Typical Trap:
Students use fire demand in sewage calculations ()


5. Solved Examples

Example 1 (Numerical – SSC JE Level)

Population = 40,000
Water demand = 135 LPCD




Answer: Average sewage flow = 4.32 MLD


Example 2 (Maximum Sewage Flow)

Peak factor = 2.5




6. MCQs (Exam Level – 30 Questions)

1. Sewerage flow is approximately what % of water supply?

A) 50%
B) 60%
C) 70–85%
D) 100%
Ans: C


2. Which component adds groundwater to sewers?

A) Inflow
B) Leakage
C) Infiltration
D) Runoff
Ans: C


3. Fire demand contributes to sewerage flow:

A) Fully
B) Partially
C) Indirectly
D) Not at all
Ans: D


4. Peak factor for sewer design is generally taken as:

A) 1
B) 1.5
C) 2–3
D) 5
Ans: C


5. Minimum sewage flow is about:

A) Equal to average
B) Half of average
C) Double of average
D) Zero
Ans: B


6. Inflow mainly enters through:

A) Pipes
B) Soil
C) Manholes
D) Pumps
Ans: C


7. If per capita water demand is 150 LPCD, per capita sewage flow is:

A) 150
B) 120
C) 100
D) 80
Ans: B


8. Sewers are designed for:

A) Average flow
B) Minimum flow
C) Maximum flow
D) Fire flow
Ans: C


9. Which is TRUE?

A) Sewage flow > water demand
B) Inflow is unavoidable
C) Infiltration is unavoidable
D) Peak factor < 1
Ans: C

10. Average sewage flow is generally taken as what fraction of water supply?

A) 0.5
B) 0.6
C) 0.8
D) 1.0
Answer: C
📝 Explanation: 70–85% ≈ 0.8 × water demand


11. Which of the following DOES NOT contribute to sewage flow?

A) Domestic water use
B) Industrial wastewater
C) Fire demand
D) Infiltration
Answer: C
📝 Trap: Fire demand never enters sewers


12. If per capita water demand is 135 LPCD, per capita sewage flow is approximately:

A) 90 LPCD
B) 100 LPCD
C) 108 LPCD
D) 135 LPCD
Answer: C
📝 Calculation: 0.8 × 135 = 108 LPCD


13. Peak sewage flow usually occurs during:

A) Midnight
B) Early morning & evening
C) Noon only
D) Night only
Answer: B


14. Infiltration in sewers is mainly due to:

A) Rainwater runoff
B) Leakage from water mains
C) Groundwater entry
D) Industrial discharge
Answer: C


15. Inflow differs from infiltration because inflow is:

A) Groundwater
B) Continuous
C) Rain-dependent
D) Unavoidable
Answer: C


16. Which factor is used to obtain maximum sewage flow?

A) Fire factor
B) Peak factor
C) Safety factor
D) Return factor
Answer: B


17. Typical value of peak factor for sewer design is:

A) 1–1.5
B) 1.5–2
C) 2–3
D) 4–5
Answer: C


18. A town has population 25,000 and water demand 135 LPCD. Average sewage flow is:

A) 2.7 MLD
B) 3.0 MLD
C) 3.375 MLD
D) 4.0 MLD
Answer: A
📝 Calculation:
Water = 25,000 × 135 = 3.375 MLD
Sewage = 0.8 × 3.375 = 2.7 MLD


19. Minimum sewage flow is approximately:

A) Equal to average
B) 0.75 × average
C) 0.5 × average
D) Zero
Answer: C


20. Sewer design capacity is based on:

A) Average flow
B) Minimum flow
C) Maximum flow
D) Fire flow
Answer: C


21. Which statement is TRUE?

A) Sewage flow > water demand
B) Inflow is unavoidable
C) Infiltration is unavoidable
D) Peak factor < 1
Answer: C


22. Industrial sewage contribution mainly depends on:

A) Population
B) Climate
C) Type of industry
D) Rainfall
Answer: C


23. If average sewage flow is 5 MLD and peak factor is 3, maximum flow is:

A) 5 MLD
B) 7.5 MLD
C) 10 MLD
D) 15 MLD
Answer: D


24. Which component can be reduced by proper sewer maintenance?

A) Domestic sewage
B) Industrial sewage
C) Infiltration
D) Inflow
Answer: D
📝 Explanation: Inflow can be controlled; infiltration is unavoidable


25. Sewage flow calculations generally exclude:

A) Industrial wastewater
B) Domestic sewage
C) Fire demand
D) Infiltration
Answer: C


26. If water demand is 10 MLD, sewage flow will MOST LIKELY be:

A) 5 MLD
B) 6 MLD
C) 8 MLD
D) 10 MLD
Answer: C


27. Unit commonly used for sewage flow in design calculations is:

A) LPCD
B) L/min
C) MLD
D) m³/s
Answer: C


28. Peak factor depends mainly on:

A) Rainfall
B) Population size
C) Pipe diameter
D) Soil type
Answer: B


29. Which statement is INCORRECT?

A) Sewage flow is less than water supply
B) Fire demand contributes to sewage
C) Infiltration adds extra flow
D) Peak factor > 1
Answer: B


30. For small towns, peak factor is generally:

A) Lower
B) Zero
C) Higher
D) Equal to 1
Answer: C
📝 Explanation: Smaller population → higher variation → higher peak factor


Last-Minute JE Memory Trick 🧠

“Sewage = Water × 0.8 | Design = Max Flow | Fire = ZERO | Infiltration stays”

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